Chapter Chapter 9: Patterns of Inheritance
 
Activities Quiz
 

1 .       The result of the following cross indicates the orange eyes are _____ black eyes. (Activity 9A)

question #1 

 incompletely dominant to
 recessive to
 codominant to
 dominant to
 larger than


2 .       If O represents the allele for black eyes (dominant) and o represents the allele for orange eyes (recessive), what would be the genotypic ratio of a cross between a heterozygous black-eyed MendAlien and an orange-eyed MendAlien? (Activity 9A) 

 1 homozygous black (OO): 1 heterozygote (black) (Oo): 1 homozygous orange (oo)
 2 homozygous black (OO): 1 heterozygote (black) (Oo): 1 homozygous orange (oo)
 1 homozygous black (OO): 0 heterozygote (black) (Oo): 1 homozygous orange (oo)
 0 homozygous black (OO): 1 heterozygote (black) (Oo): 1 homozygous orange (oo)
 0 homozygous black (OO): 0 heterozygote (black) (Oo): 1 homozygous orange (oo)


3 .       If O represents the allele for black eyes (dominant) and o represents the allele for orange eyes (recessive), what would be the phenotypic ratio of a cross between a heterozygous black-eyed MendAlien and an orange-eyed MendAlien? (Activity 9A) 

 3 black : 1 orange
 1 black : 3 orange
 0 black : 1 orange
 1black : 1 orange
 1 black : 0 orange


4 .       The result of the following cross indicates that the genotype of the female parent is _____. (Activity 9A)

question #4 

 bb
 BB
 Bb
 b
 B


5 .       The result of the following cross indicates that the genotype of the male parent is _____. (Activity 9A)

question #5 

 bb
 BB
 Bb
 b
 B


6 .       The result of the following cross indicates that genotypically the offspring _____. (Activity 9A)

question #6 

 are all bb
 are all BB
 are all Bb
 exhibit a 3 BB : 1 bb ratio
 exhibit a 1 BB : 2 Bb : 1 bb ratio


7 .       Which of these is a testcross? (Activity 9A) 

 A? x aa
 A? x AA
 A? x Aa
 A? x A?
 aa x aa


8 .       That each gamete contains a single allele of the eye color gene is an illustration of _____. (Activity 9A)

question #8 

 Beadle and Tatum's one gene–one enzyme hypothesis
 Mendel's law of segregation only
 Darwin's theory of natural selection
 Mendel's law of independent assortment only
 Both Mendel's law of segregation and Mendel's law of independent assortment.


9 .       What is the genotype of the parent with orange eyes and white skin? (Note: orange eyes are recessive.) (Activity 9B)

question #9 

 OoWw
 ooWW
 ooWw
 OOWW
 ooww


10 .       What is the genotype of the offspring? (Activity 9B)

question #10 

 OoWw
 ooWW
 ooWw
 OOWW
 ooww


11 .       In order to determine the genotype of a MendAlien with black eyes and green skin, you would cross this individual with a(n) _____ individual. (Activity 9B) 

 ooww
 OOWW
 OOww
 ooWW
 OoWw


12 .       Black eyes are dominant to orange eyes, and green skin is dominant to white skin. Sam, a MendAlien with black eyes and green skin, has a parent with orange eyes and white skin. Carole is a MendAlien with orange eyes and white skin. If Sam and Carole were to mate, the predicted phenotypic ratio of their offspring would be _____. (Activity 9B) 

 1black eyes, green skin : 1 black eyes, white skin : 1 orange eyes, green skin : 1 orange eyes, white skin
 3 black eyes, green skin : 3 black eyes, white skin : 9 orange eyes, green skin : 1 orange eyes, white skin
 1 black eyes, green skin : 3 black eyes, white skin : 3 orange eyes, green skin : 9 orange eyes, white skin
 9 black eyes, green skin : 3 black eyes, white skin : 3 orange eyes, green skin : 1 orange eyes, white skin
 There is insufficient information to determine Sam's genotype.


13 .       A cross between an individual with orange eyes and green skin and an individual with black eyes and white skin is an example of a _____ cross. (Activity 9B) 

 test
 difficult
 dihybrid
 trihybrid
 monohybrid


14 .       A phenotypic ratio of 9:3:3:1 in the offspring of a cross indicates that _____. (Activity 9B) 

 one parent is homozygous dominant and one parent is homozygous recessive
 one parent is heterozygous and one parent is homozygous recessive
 one parent is homozygous dominant and one parent is heterozygous
 both parents are heterozygous for both genes
 both parents are homozygous dominant


15 .       The observed distribution of alleles into gametes is an illustration of _____. (Activity 9B)

question #15 

 Mendel's law of segregation only
 Thienemann's rule
 Eimer's principle
 Mendel's law of independent assortment only
 Mendel's laws of segregation and independent assortment


16 .       An individual heterozygous for eye color, skin color, and number of eyes mates with an individual who is homozygous recessive for all three characters; what would be the expected phenotypic ratio of their offspring? [Hint: O = black eyes, o = orange eyes; W = green skin, w = white skin; C = two eyes, c = one eye] (Activity 9B) 

 9 black eyes, green skin, two eyes : 3 black eyes, green skin, one eye : 3 black eyes, white skin, two eyes : 1 black eyes, white skin, one eye : 9 orange eyes, green skin, two eyes : 3 orange eyes, green skin, one eye : 3 orange eyes, white skin, two eyes : 1 orange eyes, white skin, one eye
 9 black eyes, green skin, two eyes : 3 black eyes, green skin, one eye : 3 black eyes, white skin, two eyes : 1 black eyes, white skin, one eye
 1 black eyes, green skin, two eyes : 1 black eyes, green skin, one eye : 1 black eyes, white skin, two eyes : 1 orange eyes, green skin, two eyes : 1 orange eyes, white skin, two eyes : 1 orange eyes, white skin, one eye
 1 black eyes, green skin, two eyes : 1 black eyes, green skin, one eye : 1 black eyes, white skin, two eyes : 1 black eyes, white skin, one eye : 1 orange eyes, green skin, two eyes : 1 orange eyes, green skin, one eye : 1 orange eyes, white skin, two eyes : 1 orange eyes, white skin, one eye
 9 orange eyes, green skin, two eyes : 9 orange eyes, green skin, one eye : 9 orange eyes, white skin, two eyes : 1 orange eyes, white skin, one eye


17 .       A OoWw x ooww cross yields a phenotypic ratio of approximately 5 black eyes, green skin : 5 orange eyes, white skin : 1 black eyes, white skin : 1 orange eyes, green skin. Which of the following best explains these results? (Activity 9B) 

 Mendel's law of independent assortment is being violated.
 Mendel's law of segregation is being violated.
 The genes for eye color and skin color are codominant.
 The heterozygous individual is male, and the homozygous individual is female.
 Mendel's laws of segregation and independent assortment are being violated.


18 .       In the following cross the genotype of the female parent is OoWw. What is the genotype of the male parent? [Hint: O = black eyes, o = orange eyes, W = green skin, w = white skin] (Activity 9B)

question #18 

 OoWw
 OOWW
 OOWw
 OoWW
 ooWW


19 .       In a situation in which genes assort independently, what is the ratio of the gametes produced by an AaBB individual? (Activity 9B) 

 1 A : 1 B
 3 A : 1 B
 3 AB : 1 ab
 1AB : 1 aB
 3 AA : 1 BB


20 .       Mendel worked _____. (Activity 9C) 

 on the Human Genome Project
 with fruit flies
 on problems involving characters that were inherited together more often than expected by chance
 on gene mapping
 in a monastery


21 .       Andalusian chickens with the genotype CBCB are black, those with the genotype CWCW are white, and those with the genotype CBCW are gray. What is the relationship between the CB and CW alleles? (Activity 9D) 

 CB is dominant to CW
 CB is recessive to CW
 CW is dominant to CB
 The relationship between the alleles is one of incomplete dominance.
 CB and CW are codominant


22 .       Andalusian chickens with the genotype CBCB are black, those with the genotype CWCW are white, and those with the genotype CBCW are gray. What is the expected phenotypic ratio of a CBCW x CBCW cross? (Activity 9D) 

 1 black : 1 white
 3 black : 1 white
 1 black : 2 gray : 1 white
 3 gray : 1 white
 1 black : 1 gray


23 .       Andalusian chickens with the genotype CBCB are black, those with the genotype CWCW are white, and those with the genotype CBCW are gray. What is the expected genotypic ratio of a CBCW x CBCW cross? (Activity 9D) 

 1 CBCB : 1 CBCW
 3 CBCB : 1 CWCW
 1CBCB : 2 CBCW : 1 CWCW
 2 CBCB : 1 CBCW : 2 CWCW
 9 CBCB : 3 CBCW : 3 CWCB : 1 CWCW


24 .       Andalusian chickens with the genotype CBCB are black, those with the genotype CWCW are white, and those with the genotype CBCW are gray. What is the expected genotypic ratio of a CBCB x CBCW cross? (Activity 9D) 

 1CBCB : 1 CBCW
 3 CBCB : 1 CWCW
 1 CBCB : 2 CBCW : 1 CWCW
 2 CBCB : 1 CBCW : 2 CWCW
 9 CBCB : 3 CBCW : 3 CWCB : 1 CWCW


25 .       Andalusian chickens with the genotype CBCB are black, those with the genotype CWCW are white, and those with the genotype CBCW are gray. What is the expected phenotypic ratio of a CBCB x CBCW cross? (Activity 9D) 

 1 black : 1 white
 3 black : 1 white
 1 black : 2 gray : 1 white
 3 gray : 1 white
 1black : 1 gray


26 .       Based on the results of this cross, you determine that _____. (Activity 9E)

question #1 

 round eyes are dominant to vertical eyes, and the absence of a tooth is dominant to the presence of a tooth
 round eyes are dominant to vertical eyes, and the presence of a tooth is dominant to the absence of a tooth
 the allele for round eyes is linked to the allele for no tooth
 vertical eyes are dominant to round eyes, and the absence of a tooth is dominant to the presence of a tooth
 vertical eyes are dominant to round eyes, and the presence of a tooth is dominant to the absence of a tooth


27 .       The results of the following cross indicate that the _____. (Activity 9E)

question #2 

 absence of a tooth is dominant to the presence of a tooth
 two genes are linked
 MendAlien species is polyploid
 absence of a tooth is dominant to vertical eyes
 two genes assort independently


28 .       An F1 individual can produce _____ different gametes when both eye and tooth genes are considered. (Activity 9E)

question #3 

 1
 2
 3
 4
 5


29 .       Given these chromosomes, which of the choices represents the possible recombinant gametes? (Activity 9E)

question #4 

 answer #1
  answer #2
  answer #3
  answer #4
  answer #5


30 .       The results of a F1 testcross are: 250 bald head, four ears : 247 hairy head, six ears : 21 bald head, six ears : 19 hairy head, four ears. How many map units apart are the head and ear genes? (Activity 9E) 

 3.5
 3.9
 7.5
 50.5
 92.6


31 .       Which of the individuals is homozygous recessive for both of the gene pairs? (Activity 9E)

question #6 

 the female parent
 the male parent
 the F1 generation
 both the male and female parents
 both the male parent and the F1 generation


32 .       The results of the following cross indicate that the _____. (Activity 9E)

question #7 

 absence of a tooth is dominant to the presence of a tooth
 two genes are linked
 MendAlien species is polyploid
 absence of a tooth is dominant to vertical eyes
 two genes assort independently


33 .       The recombination frequency between gene A and gene B is 8.4%, the recombination frequency between gene A and gene C is 6.8%, and the recombination frequency between gene B and gene C is 15.2%. Which of these is the correct arrangement of these genes? (Activity 9E) 

 ABC
 ACB
 BCA
 CAB
 CBA


34 .       A color-blind woman mates with a male with normal color vision. Which of these results would indicate that color blindness is caused by an X-linked recessive allele? (Activity 9F) 

 Half of the sons and half of the daughters are color-blind.
 All of the daughters, and none of the sons, are color-blind.
 All of the sons, and none of the daughters, are color-blind.
 The offspring occur in a ratio of 3 color-blind : 1 normal vision.
 The offspring occur in a ratio of 9 normal vision males : 3 color-blind vision males : 3 normal vision females : 1 color-blind female.


35 .       Color blindness is an X-linked recessive trait. A color-blind man has a daughter with normal color vision. What is the genotype of the daughter? (Activity 9F) 

 XCXc
 XCXC
 XcXc
 XCY
 XcY


36 .       Color blindness is an X-linked recessive trait. A color-blind man has a daughter with normal color vision. She mates with a male who has normal color vision. What is the expected phenotypic ratio of their offspring? (Activity 9F) 

 1 normal vision female : 1 color-blind female : 1 normal vision male : 1 color-blind male
 All the offspring have normal color vision.
 2 normal vision females : 1 normal vision male : 1 color-blind male
 3 normal vision female : 1 color-blind male
 1 normal vision female : 1 color-blind male


37 .       Color blindness is an X-linked recessive trait. A color-blind man has a daughter with normal color vision. She mates with a color-blind male. What is the expected phenotypic ratio of their offspring? (Activity 9F) 

 All the offspring have normal color vision.
 2 normal vision females : 1 normal vision male : 1 color-blind male
 3 normal vision females : 1 color-blind male
 1 normal vision female : 1 color-blind female : 1 normal male : 1 color-blind male
 1 normal vision female : 1 color-blind male


38 .       Color blindness is an X-linked recessive trait. A woman who is homozygous for normal color vision mates with a color-blind male. What is the expected phenotypic ratio of their offspring? (Activity 9F) 

 2 normal vision females : 1 normal vision male : 1 color-blind male
 3 normal vision females : 1 color-blind male
 All the offspring have normal color vision.
 1 normal vision female : 1 color-blind female : 1 normal male : 1 color-blind male
 1 normal vision female : 1 color-blind male


39 .       Color blindness is an X-linked recessive trait. A color-blind woman mates with a male with normal color vision. What is the expected phenotypic ratio of their offspring? (Activity 9F) 

 1 normal vision female : 1 color-blind female : 1 normal male : 1 color-blind male
 1 normal vision daughter : 1 color-blind son
 2 normal vision females : 1 normal vision male : 1 color-blind male
 3 normal vision females : 1 color-blind male
 All the offspring have normal color vision.


40 .       Color blindness is an X-linked recessive trait. Under what conditions can an unaffected male have a color-blind daughter? (Activity 9F) 

 His mate is color-blind.
 He can't.
 He is heterozygous for color vision.
 His father is color-blind.
 His mother is color-blind.


41 .       Hypophosphatemia (vitamin D–resistant rickets) is inherited as an X-linked dominant. An unaffected woman mates with a male with hypophosphatemia. What is the expected phenotypic ratio of their offspring? (Activity 9F) 

 1 normal female : 1 female with hypophosphatemia : 1 normal male : 1 male with hypophosphatemia
 1 normal daughter : 1 son with hypophosphatemia
 1 daughter with hypophosphatemia : 1 normal son
 2 normal females : 1 normal male : 1 male with hypophosphatemia
 3 normal females : 1 male with hypophosphatemia


42 .       Hypophosphatemia (vitamin D–resistant rickets) is inherited as an X-linked dominant. A woman without hypophosphatemia and a man with hypophosphatemia have a daughter. The daughter mates with a male without hypophosphatemia. What is the expected phenotypic ratio of their offspring? (Activity 9F) 

 2 unaffected females : 1 unaffected male : 1 male with hypophosphatemia
 1 unaffected female : 1 female with hypophosphatemia : 1 unaffected male : 1 male with hypophosphatemia
 1 unaffected daughter : 1 son with hypophosphatemia
 1 daughter with hypophosphatemia : 1 unaffected son
 3 unaffected females : 1 male with hypophosphatemia


43 .       Suppose that having three nostrils is a Y-linked character. A woman with two nostrils mates with a man with three nostrils. What is the expected phenotypic ratio of their offspring? (Activity 9F) 

 1 daughter with two nostrils : 1 son with three nostrils
 1 daughter with two nostrils: 1 daughter with three nostrils: 1 son with two nostrils : 1 son with three nostrils
 2 daughters with two nostrils: 1 son with two nostrils: 1 son with three nostrils
 2 daughters with three nostrils: 1 son with two nostrils: 1 son with three nostrils
 2 sons with two nostrils: 1 daughter with two nostrils: 1 daughter with three nostrils